If it's not what You are looking for type in the equation solver your own equation and let us solve it.
3^(x+3)+1/3^x-28=0
Domain of the equation: 3^x!=0We multiply all the terms by the denominator
x!=0/1
x!=0
x∈R
(3^(x+3))*3^x-28*3^x+1=0
Wy multiply elements
(3^(x+3))*3^x-84x+1=0
We add all the numbers together, and all the variables
-84x+(3^(x+3))*3^x+1=0
We move all terms containing x to the left, all other terms to the right
-84x+(3^(x+3))*3^x=-1
| p2-10p+25=0 | | -7(-8x+5)=8(8x-5)+21 | | X²-3x-15=0 | | 4y+4=-9y+30 | | 6(3x-3)=5(-4x+6)+28 | | 3x/2+2x=5/8 | | -3x²-3x=-6 | | 28+z=-6z | | 32=4/5(b-5) | | C-15-2y=6+y | | 15-2y=6+y | | 3x-7x÷2=-10+5 | | w^2-9w+12=0 | | 6y-57=-15 | | 1.33y=40 | | 3,3+2p=4,9 | | 9=w=2 | | 8(m=1)=32 | | 2y-1÷2=17 | | 3x2+7x=40 | | 3(2(x+1)-(x+2))=2x+1 | | 8(j-12)=24 | | v=13-5 | | |3-2x|=9 | | 7p+6=62 | | X²+16x=-8 | | 2x-3=64+x-58 | | 9=z+26/6 | | 6(m-83)=48 | | -11n-4=-5n+18 | | 24=4p-12 | | 7(r-82)=49 |